Here are 24 counters on the board. If we share them fairly between four of us at this table, how many does each person get? Have a think before any hands go up.
Now a trickier one: what if there were 25 counters, not 24? What happens to the extra one?
Watch the counters deal out into equal groups. First 24 into 4, then 87 into 3. Look out for leftovers in the second one; I will slide any leftover tens across to the units myself.
Now we work through four together on the board, each one adding a wrinkle the last did not have: 24 ÷ 4 shares clean; 87 ÷ 3 carries a leftover once; 96 ÷ 4 carries once too, with one leftover ten to hold; and 235 ÷ 5 has a hundreds digit too small to share on its own. Before each deal, predict how many each group will get and whether anything will be left over.
First we work one together on the board that does not share evenly, so you can see how to write the remainder into the answer. Watch the bus-stop for 92 ÷ 5, starting on the left and carrying any leftover across.
Then, in your maths copy, set up each of these divisions using the bus-stop bracket and work each digit with the class. Carry any leftover across to the next digit, and write any final remainder into the answer with an r.
Today's challenge bank builds up step by step with fresh numbers: 48 ÷ 4 (clean share), then 78 ÷ 6 (one carry), then 736 ÷ 4 (a genuine double carry across two places), then 315 ÷ 5 (a hundreds digit too small to share), then 4,020 ÷ 4 (the lonely zero). Predict each answer, work it on the bus-stop, then check it together.
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