Here is a big number: 3,540. Without doing any dividing at all, can you already tell whether it splits evenly into 2, into 5, and into 10? Take a good look at it before anyone says a word. What is it about the number that gives the game away?
Four hundred squares show the shading for one divisibility rule at a time. Look where the shading falls, and see which tests only need the last digit and which need something more.
Now we work through some divisors together on the grid: first we shade the multiples of 2, then 4, then 6. When we shade the multiples of two, every second cell lights up, because two goes into every even number. There will be fewer cells for four, and we will check each one with the last-two-digits test. Six is the interesting one. A multiple of six has to pass two tests at once, because 6 = 2 × 3: the number must be even (the 2 test) and its digit-sum must divide by 3 (the 3 test).
Before each pattern is revealed, put a hand up and say where you think it will land. One classmate does the shading at the board while everyone else predicts aloud. A wrong prediction is completely fine — this is thinking out loud, not a test.
Before you open your copy, we will check one bigger number together for the 4 test so everyone sees how the last-two-digits rule works when the number has more than two digits.
Look at 144. Cover the hundreds digit with your finger; only the last two digits matter: 44. Does 44 divide by 4? Work it out together, then decide whether 144 itself divides by 4. That is the whole method: pull out the last two digits and test just those.
Now write these four numbers down the page in your maths copy, one under the other:
Beside each one, tick which of 2, 3, 4, 5, 9 and 10 it divides by. Next to every tick, write the test you used in a few words (for example, 'ends in 0' or 'digit-sum = 9' or 'last two digits divide by 4').
Now we shade the numbers that pass each test in turn: first every multiple of 3, then every multiple of 6 (a number that passes both the 2 test and the 3 test), then every multiple of 9, and finally every multiple of 12. A multiple of 12 is a good one to finish on, because every one of them passes both the 3 test and the 4 test at the same time. Each round asks a little more of the digit-sum rule than the last.
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