Here is a sharing problem with a twist. Four friends want to share 9 chocolate bars completely fairly, with nothing thrown away and nobody left short. Each friend gets 2 whole bars, but that leaves 1 bar over. What do you think happens to the last bar?

Each display shows counters already shared into equal groups. When a whole was left over it has been broken into tenths, then hundredths. Notice where the counters broke, and where the decimal point sits in each answer.

Today we work through these divisions together on the board, each a little harder than the last: 13 ÷ 5, then 3 ÷ 4, then 9 ÷ 8. For each one we deal the whole counters first, then break every leftover into tenths and keep sharing, breaking again into hundredths and thousandths if any tenths are still left. Predict where the decimal point will land before we check.

Today we work through these together, each one a step harder: 8 ÷ 5, then 9 ÷ 6, then 7 ÷ 8, then 11 ÷ 4. Deal the wholes, break every leftover into tenths, and read off the decimal answer. Predict how many decimal places each one will need before we check.